X=2,8x^2

Solution for X=2,8x^2 equation:

X=2.8X^2

We move all terms to the left:

X-(2.8X^2)=0

We get rid of parentheses

-2.8X^2+X=0

a = -2.8; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-2.8)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-2.8}=\frac{-2}{-5.6}
=2/5.6
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-2.8}=\frac{0}{-5.6}
=0
$